SOLUTION: 2/z-3+3/3z-9=0
Algebra.Com
Question 405377: 2/z-3+3/3z-9=0
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
2/z-3 + 3/3z-9 = 0
2/z - 3 + 3/3(z - 3) = 0 {factored 3z - 9 into 3(z - 3)}
3(z - 3)[2/z - 3 + 3/3(z - 3) = 0] {multiplied entire equation by LCD, 3(z - 3)}
3(z - 3)[2/(z - 3)] + 3(z - 3)[3/3(z - 3)] = 3(z - 3)(0) {multiplied each term by 3(z - 3)}
6 + 3 = 0 {cancelled and multiplied}
9 = 0 {simplified}
= no solution
When the variable disappears and you get a statement that is never true,
then there is no solution.
When the variable disappears and you get a statement that is always true,
then there are infinite solutions.
www.algebrahouse.com
RELATED QUESTIONS
Z^3-3z^2-4z=0 (answered by LinnW)
Find the following product:... (answered by Tatiana_Stebko)
simplify the expresion z^2 -... (answered by Cromlix)
Solve 3z+2=z-3. How do I solve this?
3z+2-z+3=0
3z-z+2+3=0
2z+5=0
2z=-5
z=-5/2... (answered by vanithaa)
solving for z... (answered by stanbon,solver91311)
3z^3... (answered by MathLover1)
Could you help me about this equation?
{{{2/(2-log(3,x))=6/(3+log(3,x))-3}}}
This is... (answered by jsmallt9)
Z^3+27/Z^3-3Z^2+9Z (answered by jsmallt9)
(3/(2z+1))-(z/(z-2))=((-3z^2+2z=58)/(2z^2-3z-2)) (answered by jsmallt9)