SOLUTION: Graph the following equation using the intercepts -4x+8y=-16 What goes on the x and y axis?!?! I'm so confused

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Question 385261: Graph the following equation using the intercepts
-4x+8y=-16
What goes on the x and y axis?!?! I'm so confused
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

x-intercept


To find the x-intercept, plug in y=0 and solve for x


-4x%2B8y=-16 Start with the given equation.


-4x%2B8%280%29=-16 Plug in y=0.


-4x%2B0=-16 Multiply 8 and 0 to get 0.


-4x=-16 Simplify.


x=%28-16%29%2F%28-4%29 Divide both sides by -4 to isolate x.


x=4 Reduce.


So the x-intercept is .


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y-intercept


To find the y-intercept, plug in x=0 and solve for y


-4x%2B8y=-16 Start with the given equation.


-4%280%29%2B8y=-16 Plug in x=0.


-0%2B8y=-16 Multiply -4 and 0 to get 0.


8y=-16 Simplify.


y=%28-16%29%2F%288%29 Divide both sides by 8 to isolate y.


y=-2 Reduce.


So the y-intercept is .


Now let's plot the points and which are the x and y intercepts respectively.





Now draw a straight line through the plotted points to graph -4x%2B8y=-16.


Graph of -4x%2B8y=-16


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim