# SOLUTION: an all day parking meter only takes dimes and quarters. If it contains 100 Coins with a total value of \$14.50, how many of each type of coin are in the meter?

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 Question 364798: an all day parking meter only takes dimes and quarters. If it contains 100 Coins with a total value of \$14.50, how many of each type of coin are in the meter?Found 2 solutions by Alan3354, josmiceli:Answer by Alan3354(31538)   (Show Source): You can put this solution on YOUR website!The 1st method, more or less traditional: d + q = 100 (100 coins) 10d + 25q = 1450 (the value) d + q = 100 --> q = 100 - d Sub for q in the 2nd eqn 10d + 25q = 1450 10d + 25(100-d) = 1450 2500 - 15d = 1450 -15d = - 1050 d = 70 q = 30 --------- A better method, imo: If all the coins were dimes, it would be \$10, = 1000 Each dime replace by a quarter adds 15 cents. 1450 - 1000 = 450 450/15 = 30 replacements --> 30 quarters, 70 dimes Answer by josmiceli(9819)   (Show Source): You can put this solution on YOUR website!Let = number of dimes Let = number of quarters given: (1) (in cents) (2) -------------- From (1): (1) Multiply both sides of (2) by and subtract from (1) (1) (2) and (2) 70 dimes and 30 quarters check: (1) (1) OK