SOLUTION: A paleontonlogist finds a bone that has 25% of the amount of carbon-14 found in living b tissue. How old is the bone?

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A paleontonlogist finds a bone that has 25% of the amount of carbon-14 found in living b tissue. How old is the bone?
Half-life of carbon-14 is 5700 years.
Let "x" be the original amount of carbon-14 in the bone.
EQUATION:
(1/4)x=x(1/2)^(t/5700)
1/4= (1/2)^(t/5700)
(1/2)^2= (1/2)^(t/5700)
2=t/5700
t = 11400 years.
Cheers,
Stan H.