Hi,

1/m+1/n = 1/t solve for t

Mulitply each term on both sides of the equation by mnt to clear the denominators

nt + mt = mn

t(n+m) = mn

t = mn/(n+m)

.

If we were to be solving for m, we would isolate m on one side of the equation

nt + mt = mn

mt- mn = -nt

m(t -n) = -nt

m = -nt/(t-n)  

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