SOLUTION: the sum of two numbers is 4, and thier product is -32.what would be thier numbers?

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Question 353627: the sum of two numbers is 4, and thier product is -32.what would be thier numbers?
Found 2 solutions by sofiyac, ewatrrr:
Answer by sofiyac(695) About Me  (Show Source):
You can put this solution on YOUR website!
x+y=4
xy=-32
from the first equation x=4-y, plug that into second one
%284-y%29y=-32
4y-y%5E2=-32
0=y%5E2-4y-32 factor
0=%28y-8%29%28y%2B4%29
so y is 8 or y is -4, now you plug those into x=4-y and solve for x
x=4-8=-4 or x=4-(-4)=8
so looks lie the answer is (-4, 8) or (8, -4). Either way, the numbers are -4 and 8.

Answer by ewatrrr(10682) About Me  (Show Source):
You can put this solution on YOUR website!
HI,
Let n represent one of the numbers. Then (4-n) is the other.
.
question states
n*(4-n) = -32
4n - n^2= -32
.
4n - n^2 + 32 = 0
multiply thru by -1
n^2 -4n -32 = 0
.
factor
(n - 8)(n + 4)= 0
n = 8
(4-n) = -4
.
-4 and 8 are the numbers
.
dheck your answers
-4 * 8 = -32