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put this solution on YOUR website!When a ball is thrown, its height in feet h after t seconds is given by the equation
h=vt-16t^2
where v is the initial upwards velocity in feet per second. If v=9 feet per second, find all values of t for which h=1 foot. Do not round any intermediate steps. Round your answer to 2 decimal places.
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h=vt-16t^2
Substitute in the value for v:
h=9t-16t^2
Substitute in the value for h:
1=9t-16t^2
Solving for t:
1=9t-16t^2
16t^2+1=9t
16t^2-9t+1=0
Solve using the quadratic formula. Doing so yields
t = {0.41, 0.15} seconds
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Detail of quadratic follows:
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=17 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: 0.410097050800552, 0.152402949199448.
Here's your graph:
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