SOLUTION: Consider two equations in point slope form. y-1=x-2 and y+5=x+4. Do the equations represents the same line? explain. write and equation in slope-intercept form for a line that is p
Algebra.Com
Question 349677: Consider two equations in point slope form. y-1=x-2 and y+5=x+4. Do the equations represents the same line? explain. write and equation in slope-intercept form for a line that is perpendicular to a line for one of the given equations. how many equations can be written for line that are perpendicular to a line for one of the given equations? explain. Please answer. i don't get it
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
SO the equations are the same line.
Put it in slope intecept
is in the form (y = mx + b) when m=1 and b = -1
To find the line perpendicular, it needs a slope that is the negative reciprocal of the given line.
There are an infinite number of lines perpendicalar to the given line (all you need to do so show that is leave the slope as is and chang ethe value of b (in this case -1) to any number.
RELATED QUESTIONS
Use the given equations to write an equation for the line in point-slope form and in... (answered by drk)
write an equation in slope-intercept form of the line with parametric equations: x=2+3t... (answered by drj)
Write an equation of a line that passes through the point (9,-1) and is parallel to... (answered by oberobic)
Question: Write Equations of the line that passes through the given points in point-slope (answered by College Student)
Hi! I am going nuts with this problem. They gave me a graph with a "launch area" and... (answered by richwmiller)
Graph the following point-slope form equations.
1. y-3=2(x-1)
2. y-5=(-1/4)x+2
(answered by ReadingBoosters)
Consider the following pair of equations:
y = 3x + 3
y = x − 1
Explain how you... (answered by josgarithmetic)
Stan thanks for your help ,i have 20 of these to do can you please help me thanks a... (answered by stanbon)
Stan thanks for your help ,i have 20 of these to do can you please help me thanks a... (answered by checkley75)