SOLUTION: Factor by using trial factors.
2(a+4)^2-(a+4)-3
2(a+4)^2-(a+4)-3=
{((a+4)+1)}*{ (2(a+4)-3)}=
(a+4)2(a+4) -3(a+4) +2(a+4)+(1*-3)
Use the f.o.i.l methods
First
Algebra.Com
Question 337270: Factor by using trial factors.
2(a+4)^2-(a+4)-3
2(a+4)^2-(a+4)-3=
{((a+4)+1)}*{ (2(a+4)-3)}=
(a+4)2(a+4) -3(a+4) +2(a+4)+(1*-3)
Use the f.o.i.l methods
First outer inner and last
Found 2 solutions by Fombitz, chiexpert:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Answer by chiexpert(48) (Show Source): You can put this solution on YOUR website!
2(a+4)^2-(a+4)-3=
{((a+4)+1)}*{ (2(a+4)-3)}=
(a+4)2(a+4) -3(a+4) +2(a+4)+(1*-3)
Use the f.o.i.l methods
First outer inner and last
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