SOLUTION: What is sine of 4theta when it equals radical 3 divided by 2?
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Question 33521
:
What is sine of 4theta when it equals radical 3 divided by 2?
Answer by
venugopalramana(3286)
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SIN(4A)=SQRT.3/2
4A=60 DEG.
A=15 DEG.
IF YOU HAVE GENERAL SOLUTIONS THEN
4A=60*(-1)^N+N*(PI)
A=15*(-1)^N+N*PI/4
