SOLUTION: Solve the system: y^2=1-x^2 y^2=x^2-3x+2

Question 331728: Solve the system: y^2=1-x^2
y^2=x^2-3x+2
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
y^2=1-x^2
y^2=x^2-3x+2
..
x^2-3x+2=1-x^2
2x^2-3x+1=0
2x^2-2x-x+1=0
2x(x-1)-1(x-1)=0
(x-1)(2x-1)=0
x=1 OR 1/2
plug the value of x to get value of y
y=0 OR sqrt 3/4
RELATED QUESTIONS
solve the system x^2+y^2=100 y=x^2-3x-10... (answered by ankor@dixie-net.com,greenestamps)

Solve the system of equation. 1. y=x^2+3x+6... (answered by Gogonati)

Solve this system using the substitution method: y = 3x - 2; y = (1/2)x -... (answered by greenestamps)

solve each system by substitution. 1) y= x+2 y= -3x+2 4) y= -3x+2 y=... (answered by solver91311)

Solve the system of equations: y-3x-2=0... (answered by jorel1380)

Solve the system: x + y + z = 4, 3x � y + z = 2, y � z =... (answered by ankor@dixie-net.com)

Solve the following system of equation,graphically:y=3x+6 (answered by mananth)

Solve the system x^2 + y = 3 x + y =... (answered by davethejackal)

solve the following system of linear inequalities by graphing x 3x-y<2,... (answered by stanbon)