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put this solution on YOUR website!the force required to lift the object is equal to mg ___ f = 525 * 9.8
the work done is the force acting over distance ___ w = 525 * 9.8 * 25
power is work per unit of time ___ (525 * 9.8 * 25) / t = 2500
t = (525 * 9.8 * 25) / 2500
the units are all in the MKS system , so "t" is in seconds