SOLUTION: A lake is stocked with 496 fish of a new variety. The size of the lake, the availability of food, and the number of other fish restrict growth in the lake to a limiting value of 31

Question 319156: A lake is stocked with 496 fish of a new variety. The size of the lake, the availability of food, and the number of other fish restrict growth in the lake to a limiting value of 3100.The population of fish in the lake after time t, in months, is given by the function, P(t) =3100/1 + 5.7e^-0.28t. After how many months will the population be 1289?
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Let P(t) = 1289
Here is your equation:
1289 = 3100 + 5.7e^(-0.28t)
Can you take it from here?
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