SOLUTION: Solve for x: 4x^2-21x^2+27=0
Algebra.Com
Question 314415: Solve for x: 4x^2-21x^2+27=0
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
4x^2-21x^2+27=0
..
-17x^2+27=0
-17x^2= -27
x^2= -27/-17
x^2 = 27/17
x= + / - sqrt (27/17)
RELATED QUESTIONS
Solve for x.... (answered by )
Solve for X... (answered by )
x^3 - 4x^2 - 21x =... (answered by scott8148)
solve for x:
7x^2 - 21x - 3 =... (answered by stanbon,TimothyLamb,josgarithmetic)
how do you solve... (answered by Fombitz)
X^2+21x-72 = 0 how to solve for x and... (answered by rapaljer)
How would I solve this equation for x?
12x^2 + 21x + 6 =... (answered by Stitch)
How do I solve for x in this equation?
12x^2 + 21x + 6 =... (answered by JBarnum)
How do I solve for x in this equation?
12x^2 + 21x + 6 =... (answered by mananth)