SOLUTION: A collection of coins is to be divided amongst 3 people so that the second person has 8 more than the first person and the third person has 6 fewer coins than the second,how many c

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 Question 312834: A collection of coins is to be divided amongst 3 people so that the second person has 8 more than the first person and the third person has 6 fewer coins than the second,how many coins should each person get? Answer by ankor@dixie-net.com(15746)   (Show Source): You can put this solution on YOUR website!Let x = total number of coins in the collection : w, y, z, the number of coins had by each person : A collection of coins is to be divided amongst 3 people so that "the second person has 8 more than the first person" y = w+8 Or w = y-8 ; " and the third person has 6 fewer coins than the second," z = y-6 : how many coins should each person get? : w + y + z = x replace w & z (y-8) + y + (y-6) = x 3y - 14 = x 3y = x + 14 y = x + : We know y > 8 and is an integer, using the above equation: when x = 13, y = 9 see if that works w = 9 - 8 w = 1 z = 9 - 6 z = 3 : Total 1 + 9 + 3 = 13 : However, there are many other solutions x=16, y=10 x=19, y=11 x=22, y=12 are just a few