# SOLUTION: A rock falls from the top of a cliff into a river 96 feet below. The equation h=-16t^2+s, s is the starting height, after a given number of seconds, t, and h is the height. How lon

Algebra ->  Algebra  -> Test -> SOLUTION: A rock falls from the top of a cliff into a river 96 feet below. The equation h=-16t^2+s, s is the starting height, after a given number of seconds, t, and h is the height. How lon      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Test Calculators and Practice Answers archive Word Problems Lessons In Depth

 Click here to see ALL problems on test Question 310286: A rock falls from the top of a cliff into a river 96 feet below. The equation h=-16t^2+s, s is the starting height, after a given number of seconds, t, and h is the height. How long would it take the rock to hit the water. can someone explain this to me in another way because I don't get it. Thanks Answer by ankor@dixie-net.com(15665)   (Show Source): You can put this solution on YOUR website!A rock falls from the top of a cliff into a river 96 feet below. The equation h=-16t^2+s, s is the starting height, after a given number of seconds, t, and h is the height. How long would it take the rock to hit the water. : Understand that gravity (on earth) accelerates an object downward 16 ft/sec every second, hence: -16t^2 and given s as the height of the object initially; 96 ft, (t=0) when it strikes the ground h = 0, right? so we have -16t^2 + 96 = 0 Simplify, divide both sides by -16, this also changes the signs and you have (t^2 - 6) = 0 t^2 = +6 t = t = 2.45 secs to hit the ground