SOLUTION: 4x^2-8x+1=0

Question 299757: 4x^2-8x+1=0
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
4x^2-8x+1=0

x=(8+-sqrt[-8^2-4*4*1])/2*4
x=(8+-sqrt64-16)/8
x=(8+-sqrt48)/8
x=(8+-6.9282)/8
x=(8+6.9282)/8
x=14.9282)/8
x=1.866 ans.
x=(8-6.9282)/8
x=1.0718/6
x=.134 ans.
RELATED QUESTIONS
8x-4x-1=2 (answered by ReadingBoosters)

Solve: 4x^2 - 8x + 1 =... (answered by JBarnum)

4x^2+8x+5=0 (answered by jim_thompson5910,stanbon)

solve by factoring... (answered by solver91311)

Please solve: 4x^2+8x-4=0 (answered by chibisan,stanbon)

3/4x^2+8x+20=0 (answered by ewatrrr)

(6x^2-8x+6) +... (answered by LtAurora)

(6x^2-8x+6) + (-4x^2-8x-1) (answered by CubeyThePenguin)

(6x^2-8x+6) +... (answered by CubeyThePenguin)