SOLUTION: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height
Algebra ->
Algebra
-> Test
-> SOLUTION: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height
Log On
Question 296981: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height that the ball will reach? Answer by richwmiller(9143) (Show Source):
