# SOLUTION: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height

Algebra ->  Algebra  -> Test -> SOLUTION: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height      Log On

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 Question 296981: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height that the ball will reach?Answer by richwmiller(9143)   (Show Source): You can put this solution on YOUR website!at 1.5 seconds 36 ft high