SOLUTION: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height
Algebra.Com
Question 296981: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height that the ball will reach?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
at 1.5 seconds 36 ft high
RELATED QUESTIONS
the height in feet for a ball thrown upward at 48 feet per second is given by... (answered by Alan3354)
The height in feet for a ball thrown upward at 48 feet per second is given by
s(t)=... (answered by nerdybill,haileytucki)
The height in feet for a ball thrown upward at 48 feet per second is given by s(t) =... (answered by josmiceli)
The height in feet for a bal thrown upward at 48 feet per second is given by... (answered by solver91311)
22.) Find he exact solution.
The height in feet for a ball thrown upward at 48 feet... (answered by nerdybill)
Hi, I am having trouble figuring out this problem. Would someone please help me figure... (answered by mathsteacher)
The height in feet for a ball thrown upward at 48 feet per
second is given by... (answered by Earlsdon)
The height in feet for a ball thrown upward at 48 feet per second is given by
s(t)=... (answered by Alan3354)
A ball is thrown vertically upward with an initial velocity of 48 feet per second. If the (answered by lwsshak3)