SOLUTION: Find a number so that six sevenths of it exceeds four fifths of it by 2.

Question 287982: Find a number so that six sevenths of it exceeds four fifths of it by 2.
Found 3 solutions by Grinnell, stanbon, unlockmath:
Answer by Grinnell(63)   (Show Source): You can put this solution on YOUR website!
6/7x =4/5x + 2
This is how we set this up. Review the translation words for when you are
translating from English to Math.
exceeds...by two MEANS IS TWO UNITS GREATER THAN SO (STAY WITH ME HERE) anything between the exceeds and the by (...) we will add two to. In this case we add 2 to 4/5x. THIS IS CRUCIAL.
OK back at the ranch...multiply thru by 35...
30x =28x+70
2x=70
x=35. The answer is 35.
30 = 28 + 2!!! Check.

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Find a number so that six sevenths of it exceeds four fifths of it by 2.
----------------------------
Let the answer be "x":
---
Equation:
(6/7)x-(4/5)x = 2
(6/7 - 4/5)x = 2
------
(2/35)x = 2
x = 35
=================================
cheers,
Stan H.
Answer by unlockmath(1688)   (Show Source): You can put this solution on YOUR website!
Hello,
Let's have "x" be the number so we can set up the following equation as:
6/7(x)-2=4/5(x) Multiply both sides by 35 to get:
30x-70=28x Subtract 30x from both sides to get:
-70=-2x Divide both sides by -2 to get:
x=35
Make sense?
(Hint: The word "of" in math usually means "multiply" or "times")
Check out a book I wrote at:
www.math-unlock.com
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