SOLUTION: how do you factor each trinomial completely? -a^2-10a+21 -x^2+9x+20

Question 272072: how do you factor each trinomial completely?
-a^2-10a+21

-x^2+9x+20
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
-a^2-10a+21

a=(10+-sqrt(-10^2-4*-1*21])/2*-1
a=(10+-sqrt100+84])/-2
a=(10+-sqrt184)/-2
a=(10+-13.56)/-2
a=23.56/-2
a=-11.78 ans.
a=(10-13.56)/-2
a=-3.56/-2
a=1.78 ans.
---------------------------
-x^2+9x+20

x=(-9+-sqrt[9^2-4*-1*20])/2*-1
x=(-9+-sqrt[81+80)/-2
x=(-9+-sqrt161)/-2
x=(-9+-12.69)/-2
x=(-9+12.69)/-2
x=3.69/-2
x=-1.845 ans.
x=(-9-12.69)/-2
x=-21.69/-2
x=10.845 ans.
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