SOLUTION: find the line of symmetry f(x)=-(x+4)^2+9

Question 266385: find the line of symmetry f(x)=-(x+4)^2+9
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
f(x)=-(x+4)^2+9
f(x)=-(x^2+8x+16)+9
f(x)=-x^2-8x-16+9
f(x)=-x^2-8x-7 complete the square.
x^2+8x+16=-7+16
(x+4)^2=9
x+4=0
x=-4
Axis of symetry is x=-4
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -x^2 -8x -7).
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