I am working in week eight of math 116. I am on problem 13 which the first part is a numberline graph. I was asked to choose the compound inequality, which I was able to do. However the second part of the question askes me to write the solution in interval notation. The problem is x<9 and x>=-6. Does anyone know how to do this problem? If so I really need some help.
Now can be written as
Now you have
Reverse these:
Now you can write these together as a continued inequality
like this:
That says x is between -6 and 9, INclusive of -6,
but EXclusive of 9, so on a number line the graph is
-------@============================================o---------
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12
Notice that there is a closed circle at -6 and an open circle
at 9. The interval notation is an abbreviation of the above
graph. The left endpoint is -6 and the right endpoint is 9,
so the interval notation is
[-6,9)
The bracket "[" on the left next to the -6 indicates that the -6
is included, the parentheses ")" on the right indicates that the
9 is NOT included.
Edwin