SOLUTION: Solve for x to the nearest tenth: {{{6^(2x-1) = 73}}}
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Question 261034: Solve for x to the nearest tenth:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Take the natural log (or base 10 log if you like -- doesn't matter) of both sides:
\ =\ \ln\left(73\right))
Use
\ =\ n\log_b(x))
to write:
\ln\left(6\right)\ =\ \ln\left(73\right))
Multiply both sides by })
\ =\ \frac{\ln\left(73\right)}{\ln\left(6\right)})
Add 1 to both sides:
}{\ln\left(6\right)}\ +\ 1)
Multiply both sides by 
}{2\ln\left(6\right)}\ +\ \frac{1}{2})
Use
to write:
}{\ln\left(36\right)}\ +\ \frac{1}{2})
A little calculator work and a round-off should get you the answer you need.
John
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