SOLUTION: I'm not sure that I'm asking this in the right section, but I'm not really sure where I would need to ask it anyways.
The answer is:
3p/2
The problem is this:
((2p-2)/p)
Algebra.Com
Question 243368: I'm not sure that I'm asking this in the right section, but I'm not really sure where I would need to ask it anyways.
The answer is:
3p/2
The problem is this:
((2p-2)/p) * ((6p^2)/(8p*8))
I'm not sure how to get to that answer
and I think I don't have a clue on how to even start this one.
I started by put the 2 sides together
(2p-2)6p^2
----------
p(8p*8)
3(x-1)
Found 2 solutions by Alan3354, Gattsbr:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The answer is:
3p/2
The problem is this:
((2p-2)/p) * ((6p^2)/(8p*8))
I'm not sure how to get to that answer
and I think I don't have a clue on how to even start this one.
I started by put the 2 sides together
(2p-2)6p^2
----------
p(8p*8)
----------
That's a good start
=
Cancel the p^2 terms
=
=
= 3(p-1)/16
Answer by Gattsbr(1) (Show Source): You can put this solution on YOUR website!
3(p-1)/16 is incorrect
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