SOLUTION: Have a review to do for an upcoming text and I forgot how to solve: Solve 3^(x^(2)+4x)) = 1 / 27

SOLUTION: Have a review to do for an upcoming text and I forgot how to solve: Solve 3^(x^(2)+4x)) = 1 / 27

Algebra.Com

Question 242322: Have a review to do for an upcoming text and I forgot how to solve:
Solve 3^(x^(2)+4x)) = 1 / 27
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve 3^(x^(2)+4x)) = 1 / 27
------------
1/27 = 3^-3 so
x^2 + 4x = 3
x^2 + 4x + 3 = 0
------
x = -1
x = -3

RELATED QUESTIONS
I have an algebra review and forgot how to solve these types of equations..... (answered by stanbon)

I have to solve for (u) but I forgot how to do this problem...... (answered by rfer)

hey tutor, i have a question on how to solve for 3 consecutive integers. i need help... (answered by KMST)

I understand the concepts behind natural logarithms and solving for an exponent, but on... (answered by Alan3354)

I NEED EXPLANATION IN A COUPLE OF MATH PROBLEMS they are all odd the answers are in the... (answered by oscargut)

I have a math hw problem for my semester review and I forgot how to do it Two sides of (answered by palanisamy,stanbon)

I wanted to know how to solve by graphing. -3x-y=-10 4x-4y=8 (-1,3)or (1,3) or... (answered by mananth)

how do I use substitution to solve the linear system for X + 3/4y = 3/4 2y = 4x +... (answered by aussie7us)

Simplify by removing a factor of 1. x^2-4x+3 over x^2+3x-18 I am not finding any... (answered by stanbon)