You can
put this solution on YOUR website!compute how many four-digit integers use each of the digits 3,4,7,8 once and are divisible by 11
3784 = 11*344
3487 = 11*317
4378 = 11*398
4873 = 11*443
7348 = 11*668
7843 = 11*713
compute the sum of the digits of the integers from 350 to 400, inclusive
51 numbers. The average = (350+400)/2 = 375
51*375 = 19125
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If you mean the sum of individual digits:
In the 100s position there are:
50 3's and 1 4 = 154
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In the 10s position there are:
10 5's, 10 6's, 7's, 8's and 9's
--> 50 digits with average of 7 = 350
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In the 1's there are:
0-9 5 times
= 5*9*avg(1-9) = 5*9*5 = 225
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154+350+225 = 729
729 = 3^6, but I don't see any connection