SOLUTION: Point (1, –2) , m = –5.

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Question 225964: Point (1, –2) , m = –5.
Found 2 solutions by rfer, drj:
Answer by rfer(16322)   (Show Source): You can put this solution on YOUR website!
y=mx+b
y=-5x+3
Answer by drj(1380)   (Show Source): You can put this solution on YOUR website!
Point (1, –2) , m = –5.

I assume you want to write the slope intercept form of the equation of the line through the given point (1,-2) with the given slope m=-5.

Step 1. The slope-intercept form is given as y=mx+b where m is the slope and b is the y-intercept when x=0 or at point (0,b).

Step 2. Now we have to find the line with slope m=-5 going through point (1,-2).

Step 3. Given two points (x1,y1) and (x2,y2), then the slope m is given as



Step 4. Let (x1,y1)=(1,-2) or x1=1 and y1=-2. Let other point be (x2,y2)=(x,y) or x2=x and y2=y.

Step 5. Now we're given . Substituting above values and variables in the slope equation m yields the following steps:





Step 6. Multiply x-1 to both sides to get rid of denominator on right side of equation.





Step 7. Add -2 to both sides of the equation





Step 7. ANSWER: The equation in slope-intercept form is where the slope m=7 and the y-intercept b=-5.

Note: the above equation can be rewritten in standard form as



And the graph is shown below which is consistent with the above steps.

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 3/5 = 0.6.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 3/1 = 3.
  • Slope is -5/1 = -5.
  • Equation in slope-intercept form: y=-5*x+3.



I hope the above steps and explanation were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
http://www.FreedomUniversity.TV
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