SOLUTION: Hey there, Could someone please help me with the following homework question? It would be a great help. Solve the following equation for 0 lesser than and equal to x lesser than

Question 195626: Hey there, Could someone please help me with the following homework question? It would be a great help.
Solve the following equation for 0 lesser than and equal to x lesser than and equal to 2 pi.
sinx = cos2x (5 marks)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
sinx = cos2x
sin(x) = 1-2sin^2(x)
2sin^2 + sin - 1 = 0
(2sin - 1)(sin + 1) = 0
sin = 1/2, sin = -1
----------------------
x = pi/6, 5pi/6 (from 1/2)
x = 3pi/2 (sin = -1)

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