SOLUTION: if (px+3y+9)+ (7x-11y+5)= 3x-qy+14, find the value of p and q

Question 193681: if (px+3y+9)+ (7x-11y+5)= 3x-qy+14, find the value of p and q
Answer by anantha(86) (Show Source): You can put this solution on YOUR website!
sol:px+3y+9---------------(1)st equation
7x-11y+5---------------(2) equation
these two equations are on left hand side
first adding these two equations

=(px+7x)+(3y-11y)+(9+5)
=(p+7)x+(3-11)y+(14)
=(p+7)x+(-8)y+(14)
=(p+7)x-8y+14 (i.e;(+)(*)(-)=-)
now take right hand side equation
3x-qy+14
now equating left and right handside equations
(p+7)x-8y+14 = 3x-qy+14
comparing x coficient and y coficients on both sides
here p+7 is lefthandside x coficient and 3 is righthandside coficient
p+7=3
p=3-7=-4;
comparing y coficients on both sides
-8=-q
q=8
answer is p=-4,q=8
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