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put this solution on YOUR website!Area bounded by x^2=y, x=1 and x-axis.
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y = x^2 passes thru the Origin, so it's the area under the curve from x = 0 to x = 1.
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Integral(x^2) = x^3/3 + C
Area = f(1) - f(0)
= 1/3 - 0
Area = 1/3 square units