SOLUTION: The equation of the circle with radius 2 and center at (-1,3). Thanks for the big help.. Kindly put the solution..

Question 187740: The equation of the circle with radius 2 and center at (-1,3).

Thanks for the big help.. Kindly put the solution..
Answer by uday1435(57) (Show Source): You can put this solution on YOUR website!
(x � g)^2 +(y � h)^2 = r^2
So for the given center and radius
(x + 1)^2 +(y � 3)^2 = 4
x^2 + 2x + 1 + y^2 � 6y +9 = 4
x^2 + y^2 + 2x � 6y + 6 = 0 is the required equation
If you still require further clarifications please write to
udayakumar.t.r@gmail.com

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