SOLUTION: Please help. Carol has a box with a length, width, and height of 12 inches. She needs a box that is 3 inches longer, not as high, yet still has almost exactly the same volume. a

Algebra ->  Algebra  -> Test -> SOLUTION: Please help. Carol has a box with a length, width, and height of 12 inches. She needs a box that is 3 inches longer, not as high, yet still has almost exactly the same volume. a      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 175744: Please help.
Carol has a box with a length, width, and height of 12 inches. She needs a box that is 3 inches longer, not as high, yet still has almost exactly the same volume.
a. What is the volume of the box she has now?
b. What are the dimensions of the new box?
c. What is the volume of the new box?
Thank You. Please explain your answer.

Answer by Fombitz(13823) About Me  (Show Source):
You can put this solution on YOUR website!
a.) Volume of a cube with side s.
V=s%5E3=12%5E3=+1728
The box has 1728 cubic inches of volume.
.
.
.
b.) Length=15 (12+3),Height<12, Width is unspecified.
The volume for this box would be
V=L%2AH%2AW
V=15%2AH%2AW
1728=15%2AH%2AW
H%2AW=115.2
If H is less than 12, then
W%3E9.6
There is not enough information to complete the problem.
The height and width are allowed to vary, but should follow
H%2AW=115.2
to achieve the same volume as before.
Are the width and height supposed to be the same?