SOLUTION: When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original
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Question 170691: When the digits of a two-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?
Thanks.
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
lets call the 10 digit number a and the ones digit number b.
:
remember a two digit number take 35 for instance can be written as 3(10)+5(1)
with that in mind lets write and equation based on that understanding.
:
10(a)+1(b)=(10(b)+1(a))+9--->9a-9b=9--->a-b=1....eq 1
a+b=11.................................eq 2
:
add the 2 equations together to eliminate the b term.
:
2a=12
:
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