# SOLUTION: a picture is 1 inch longer than it is wide. it is put into a frame one half inch wider on every side. find the area of the picture if the frame area is eight inches squared.

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 Question 166509: a picture is 1 inch longer than it is wide. it is put into a frame one half inch wider on every side. find the area of the picture if the frame area is eight inches squared.Answer by ankor@dixie-net.com(15639)   (Show Source): You can put this solution on YOUR website!a picture is 1 inch longer than it is wide. it is put into a frame one half inch wider on every side. find the area of the picture if the frame area is eight inches squared. : Let x = width of the picture then (x+1) = length of the picture : Frame 1/2 inch wider all around, therefore x + 2(.5)= (x+1) = width of the frame and (x+1) + 2(.5) = x + 1 + 1 = (x+2) = length of the the frame : Frame area given as 8 sq/in, therefore (x+1)*(x+2) = 8 FOIL x^2 + 3x + 2 = 8 x^2 + 3x + 2 - 8 = 0 : a quadratic equation x^2 + 3x - 6 = 0 Use the quadratic formula to find x: a=1; b=3; c=-6 : You should get a positive solution about x = 1.37 inches is the width of the pic then, 2.37 = length : A = 1.37 * 2.37 A = 3.25 sq/in is the picture : : Check solution: Frame dimensions 2.37 by 3.37 Frame area = 2.37 * 3.37 = 7.77 ~ 8 sq/in as given