SOLUTION: 37.) Show a complete solution to the problem. If the perimeter of a rectangle is 20 feet and the diagonal is 2 sqrt (13) feet then what are the length and width?

Question 165247: 37.) Show a complete solution to the problem.
If the perimeter of a rectangle is 20 feet and the diagonal is 2 sqrt (13) feet then what are the length and width?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If the perimeter of a rectangle is 20 feet and the diagonal is 2 sqrt (13) feet then what are the length and width?
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2(L+W) = 20
L^2 + W^2 = (2sqrt(13))^2
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Simplify:
L + W = 10
(10-W)^2 + W^2 = 4*13
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Solve for W:
100 - 20W + 2W^2 = 52
W^2 - 10W + 24 = 0
(W-4)(W-6) = 0
Width = 4 feet and Length = 6 feet
OR
Width = 6 feet and Length = 4 feet
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Cheers,
Stan H.

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