SOLUTION: 14.) Solve each equation by using the quadratic formula -8q^2-2q+1=0

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Question 164959This question is from textbook Elementary and Intermediate
: 14.) Solve each equation by using the quadratic formula
-8q^2-2q+1=0
This question is from textbook Elementary and Intermediate

Found 2 solutions by checkley77, Electrified_Levi:
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
-8q^2-2q+1=0

q=(2+-sqrt[-2^2-4*-8*1])/2*-8
q=(2+-sqrt4+32)/-16
q=(2+-sqrt36)/-16
q=(2+-6)/-16
q=(2+6)/-16
q=(8/-16
q=-1/2 answer.
q=(2-6)/-16
q=-4/-16
q=1/4 answer.

Answer by Electrified_Levi(103)   (Show Source): You can put this solution on YOUR website!
Hi, Hope I can help,
.
14.) Solve each equation by using the quadratic formula

.
First we have to but the equation in the standard form
.
It is already in that form. (x is replaced with q)
.
,
.
A = (-8)
B = (-2)
C = 1
.
We have to know the quadratic equation, which is
.

.
We can replace A with (-8), B with (-2), C with "1"
.
= = = = =
.
There are two answers that "q" can equal ( + 6, - 6 )
.
= =
.
= =
.
q can be , and
.
You can check by replacing "q" with "", and "" in the original equation,
.
q = , = = = = = (True)
.
q = , = = = = = = (True)
.
q =
.
q =
.
Here is the graph of the equation
.

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Where the curved line crosses the x axis, are the solutions to the equation
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The curved line crosses where "q"(or "x") = , it also crosses the x axis where "q"(or "x") =
.
The two solutions are
.
q =
.
q =
.
Hope I helped, Levi

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