SOLUTION: 3y/3y-6 + 8/y^2-4 = 2y/2y+4 I got thi problem wrong in my test please help me

Question 162854This question is from textbook beginning and intermidate algebra
: 3y/3y-6 + 8/y^2-4 = 2y/2y+4 I got thi problem wrong in my test please help me This question is from textbook beginning and intermidate algebra

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
+ =
:
First, recognize that you can factor out 3 and 2 in the denominators
Note that y^2-4 is the "difference of squares"
+ =
:
Note that the 3's and 2's will cancel leaving:
+ =
:
Multiply equation by (x-2)(x+2), results:
y(y+2) + 8 = y(y-2)
:
y^2 + 2y + 8 = y^2 - 2y
:
arrange the variables on the left, and numbers on the right
y^2 - y^2 + 2y + 2y = -8
:
4y = -8
y =
y = -2
This should be the solution, but when we substitute -2 for y in the original
equation, we end up with 2 denominators of 0, which we can't have
therefore we have to say, " No solution"
RELATED QUESTIONS
Can you please tell me if i got these correct? Im doing a practice test to study for my... (answered by Edwin McCravy,solver91311)

thi is actually a problem from a exam. It is my study for my final but i got it wrong.... (answered by checkley77)

I can not figure this problem out...please help me. I am not getting any one of these... (answered by mathchemprofessor,sae00)

Completing the square 1. X^4+64y^4 2. X^4+y^2+25 3. X^4-11x^2y^2+y^4 Please do... (answered by dkppathak)

Completing the square 1. X^4+64y^4 2. X^4+y^2+25 3. X^4-11x^2y^2+y^4 Please do... (answered by KMST)

Solve by addition 2x-3y=-2 5x=2y-9 I did... 5x=2y-9 I triex to make the... (answered by rothauserc,Alan3354)

Im doing a practice test to study for my real test. I would like to know if i got th... (answered by MathLover1)

Can you please help me? This problem isn't in the book. 3(y-2)+y(1+2)=4 3y-6+1y+2y=4... (answered by venugopalramana,Earlsdon,anjulasahay)

The problem is: [(3y-4)/(49-y^2)] + [(2y+1)/(y-7)] I know i need to find the LCD... (answered by scott8148)