SOLUTION: Factor each polynomial, if the polynomial is prime say so
3x^3y^2-3x^2y^2+3xy^2
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Question 162337This question is from textbook Elementary and Intermediate
: Factor each polynomial, if the polynomial is prime say so
3x^3y^2-3x^2y^2+3xy^2
This question is from textbook Elementary and Intermediate
Answer by gonzo(654) (Show Source): You can put this solution on YOUR website!
equation is
looks like you can factor out 3*x*y^2 to get
quadratic formula to find the roots of is
and
looking at and using the quadratic formula, it looks like the solution to that quadratic equation is not real since
the part of the equation under the square root sign is negative as shown below.
in the equation
a = 1
b = -1
c = 1
4*a*c = 4
b^2 = 1
equals = which is negative so you don't have a real solution.
---
the answer appears to be
appears to be prime because it can't be factored any further.
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