SOLUTION: hey, could you please solve this problem for me, and thanks, A rectangle, 3cm longer than it is wide, has a diagonal 15cm long. find the dimensions fo the rectangle. i will

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Question 160319: hey,
could you please solve this problem for me, and thanks,
A rectangle, 3cm longer than it is wide, has a diagonal 15cm long. find the dimensions fo the rectangle.
i will be waiting for the answer,
thank you again,

Found 2 solutions by Edwin McCravy, checkley77:
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!

Draw the rectangle and its diagonal, putting
the length  on the diagonal:



Label the width .

Since the length is 3 cm longer than the width,

label the length 



Erase the upper left half of the rectangle:



That leaves a right triangle, with legs 

 and hypotenuse .

So we use the Pythagorean theorem:

 with 















Divide through by 2:





Think of two integers which
have product -108 and combine
to give +3:

They are -9 and +12, so the
left sides factors as:



Use the zero-factor principle



We choose the positive value for the width,

Therefore the width = 9cm
and the length = w+3 = 9+3 = 12cm

Edwin


Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
L=W+3
HERE YOU HAVE A RIGHT TRIANGLE OF SIDES L & W WITH AN HYPOTENUSE=15
THUS USING THE PYTHAGOREAN THEOREM (A^2+B^2=C^2)WE GET:
(W+3)^2+W^2=15^2
W^2+6W+9+W^2=225
2W^2+6W+9-225=0
2W^2+6W-216=0
2(W^2+3W-108)=0
2(W-9)(W+12)=0
W-9=0
W=9 FOR THE WIDTH
L=9+3=12 FOR THE LENGTH.
PROOF:
9^2+12^2=15^2
81+144=225
225=225

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