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SOLUTION: solve for 'a' 3a=c-a(b+d) answer is a=c/3+b+d with a negative 'a', how do you get to the single 'a' on the right?
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Question 152127
This question is from textbook
elementary and intermediate algebra
:
solve for 'a'
3a=c-a(b+d)
answer is a=c/3+b+d
with a negative 'a', how do you get to the single 'a' on the right?
This question is from textbook
elementary and intermediate algebra
Answer by
vleith(2950)
(
Show Source
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Given
First use distribution to expand the right side
Now move all the terms with an 'a' in them to the same side
Basically we added ab+ad to both sides
Now use distribution to pull the a out of the three terms on the left side
Now divide both sides by (3+b+d)