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Question 152127This question is from textbook elementary and intermediate algebra
: solve for 'a'
3a=c-a(b+d)
answer is a=c/3+b+d
with a negative 'a', how do you get to the single 'a' on the right?
This question is from textbook elementary and intermediate algebra
: solve for 'a'
3a=c-a(b+d)
answer is a=c/3+b+d
with a negative 'a', how do you get to the single 'a' on the right?

Answer by vleith(1174) About Me  (Show Source):
You can put this solution on YOUR website!
Given 3a=c-a(b+d)
First use distribution to expand the right side
3a=c-ab -ad
Now move all the terms with an 'a' in them to the same side
3a + ab + ad = c Basically we added ab+ad to both sides
Now use distribution to pull the a out of the three terms on the left side
a*(3+b+d) = c
Now divide both sides by (3+b+d)
a = c / (3+b+d)