SOLUTION: solve for 'a' 3a=c-a(b+d) answer is a=c/3+b+d with a negative 'a', how do you get to the single 'a' on the right?

Algebra ->  Algebra  -> Test -> SOLUTION: solve for 'a' 3a=c-a(b+d) answer is a=c/3+b+d with a negative 'a', how do you get to the single 'a' on the right?       Log On

Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 152127This question is from textbook elementary and intermediate algebra
: solve for 'a'
3a=c-a(b+d)
answer is a=c/3+b+d
with a negative 'a', how do you get to the single 'a' on the right?
This question is from textbook elementary and intermediate algebra

Answer by vleith(2825) About Me  (Show Source):
You can put this solution on YOUR website!
Given 3a=c-a%28b%2Bd%29
First use distribution to expand the right side
3a=c-ab+-ad
Now move all the terms with an 'a' in them to the same side
3a+%2B+ab+%2B+ad+=+c Basically we added ab+ad to both sides
Now use distribution to pull the a out of the three terms on the left side
a%2A%283%2Bb%2Bd%29+=+c
Now divide both sides by (3+b+d)
a+=+c+%2F+%283%2Bb%2Bd%29