SOLUTION: solve for 'a' 3a=c-a(b+d) answer is a=c/3+b+d with a negative 'a', how do you get to the single 'a' on the right?

Question 152127This question is from textbook elementary and intermediate algebra
: solve for 'a'
3a=c-a(b+d)
answer is a=c/3+b+d
with a negative 'a', how do you get to the single 'a' on the right?
This question is from textbook elementary and intermediate algebra

Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
Given
First use distribution to expand the right side

Now move all the terms with an 'a' in them to the same side
Basically we added ab+ad to both sides
Now use distribution to pull the a out of the three terms on the left side

Now divide both sides by (3+b+d)

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