SOLUTION: 60% of the area of Rectangle A is the same as 80% of the area of Rectangle B. Rectangle B is 25cm2 smaller than Rectangle A. Given that they both have a length of 25 cm, find the d

Algebra ->  Algebra  -> Test -> SOLUTION: 60% of the area of Rectangle A is the same as 80% of the area of Rectangle B. Rectangle B is 25cm2 smaller than Rectangle A. Given that they both have a length of 25 cm, find the d      Log On

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Question 149785: 60% of the area of Rectangle A is the same as 80% of the area of Rectangle B. Rectangle B is 25cm2 smaller than Rectangle A. Given that they both have a length of 25 cm, find the difference in their perimeter.
Rmks: Pls try not to use algebra.
Answer by kmcruz09(38) About Me  (Show Source):
You can put this solution on YOUR website!
I don't think you can solve this one without using algebra. Anways, here's the solution.
60% of the area of Rectangle A is the same as 80% of the area of Rectangle B. Rectangle B is 25cm2 smaller than Rectangle A. Given that they both have a length of 25 cm, find the difference in their perimeter.
let x = width of rectangle A
let y = width of rectangle B
then Area of rectangle A = 25x
and Area of rectangle B = 25y
0.6%2825x%29+=+0.8%2825y%29
150x+=+200y
x+=+4y%2F3
25x+=+25y+%2B+25
x+=+y%2B1
y%2B1=4y%2F3
3y%2B3=4y
y=3
x=4
PERIMETERa = 2%28x%2B25%29
= 58
PERIMETERb = 2%28y%2B25%29
= 56
PERIMETERa - PERIMETERb = 2cm