SOLUTION: 60% of the area of Rectangle A is the same as 80% of the area of Rectangle B. Rectangle B is 25cm2 smaller than Rectangle A. Given that they both have a length of 25 cm, find the d

Question 149785: 60% of the area of Rectangle A is the same as 80% of the area of Rectangle B. Rectangle B is 25cm2 smaller than Rectangle A. Given that they both have a length of 25 cm, find the difference in their perimeter.
Rmks: Pls try not to use algebra.
Answer by kmcruz09(38) (Show Source): You can put this solution on YOUR website!
I don't think you can solve this one without using algebra. Anways, here's the solution.
60% of the area of Rectangle A is the same as 80% of the area of Rectangle B. Rectangle B is 25cm2 smaller than Rectangle A. Given that they both have a length of 25 cm, find the difference in their perimeter.
let x = width of rectangle A
let y = width of rectangle B
then Area of rectangle A = 25x
and Area of rectangle B = 25y

PERIMETERa =
=
PERIMETERb =
=
PERIMETERa - PERIMETERb = 2cm
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