SOLUTION: Hi, I am really stuck on this question. Can someone help me please??
A secretary periodically checks to see how many of the three lines into the office are busy. her finding fo
Algebra.Com
Question 148186: Hi, I am really stuck on this question. Can someone help me please??
A secretary periodically checks to see how many of the three lines into the office are busy. her finding for one week were the following.
No. lines busy Frequency
0 20
1 65
2 25
3 10
Let the random variable X be the number of lines busy. Find the probability distribution of X.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
20+65+25+10=120
.
0 20/120=.1667
1 65/120=.5417
2 25/120=.2083
3 10/120=.0833
-----------------
========>1.0000
.
Ed
RELATED QUESTIONS
I am having a really hard time trying to figure out this question please help,all I know... (answered by josmiceli)
Hi, I am really stuck on this one! Can someone please help? I need to solve this by... (answered by Theo)
Hi, I am really having a hard time analyzing this one, I hope someone could help me on... (answered by Earlsdon,venugopalramana)
A secretary periodically checks to see how many of the 3 lines into the office are busy. (answered by Edwin McCravy)
I'm a bit confused on how to approach this question. Please help me out.
How many... (answered by ikleyn)
Hi Tutors, Can someone see if I did this problem right and if not can you tell me what I... (answered by josmiceli)
Hi you all I really need help with this question.....Scores on the Standford-Binet I... (answered by stanbon)
Hello, I am having a really hard time understanding this question. Can someone please... (answered by lwsshak3)
I am really stuck on these two problems. Can someone please explain to me how to do them? (answered by vleith)