SOLUTION: {{{ (3x^3-19x^2+27x+4) / (x-4)}}}={{{ (3x^3-19x^2+27x+4) / (x-4)}}}=
Algebra.Com
Question 143673: ==
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
doing synthetic division
-- 3 -- -19 -- 27 -- 4
4 ---- 12 -- -28 -- -4
-- 3 -- -7 -- -1 -- 0
so ==
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