SOLUTION: Factor: st + 5b – bs – 5t A) (s – 5)(t + b) B) (s – 5)(t – b) C) (s + 5)(t – b) D) The expression is prime.

Algebra ->  Algebra  -> Test -> SOLUTION: Factor: st + 5b – bs – 5t A) (s – 5)(t + b) B) (s – 5)(t – b) C) (s + 5)(t – b) D) The expression is prime.       Log On

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Question 140010: Factor: st + 5b – bs – 5t
A) (s – 5)(t + b)
B) (s – 5)(t – b)
C) (s + 5)(t – b)
D) The expression is prime.

Answer by jim_thompson5910(21667) About Me  (Show Source):
You can put this solution on YOUR website!
st%2B5b-bs-5t Start with the given expression


st-bs%2B5b-5t Rearrange the terms


%28st-bs%29%2B%285b-5t%29 Group like terms


s%28t-b%29-5%28-b%2Bt%29 Factor out the GCF "s" from the first group. Factor out the GCF -5 from the second group


s%28t-b%29-5%28t-b%29 Rearrange -b%2Bt in the second group to get t-b


%28s-5%29%28t-b%29 Combine like terms


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Answer:

So st%2B5b-bs-5t factors to %28s-5%29%28t-b%29