SOLUTION: A freight train and a passenger train start toward each other at the same time from two towns that are 500 miles apart. After three hours the trains are still 80 miles apart. If th

Question 138694: A freight train and a passenger train start toward each other at the same time from two towns that are 500 miles apart. After three hours the trains are still 80 miles apart. If the rate of the passenger train is 20 miles per hour faster than the rate of the freight train, find the rate of each train.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A freight train and a passenger train start toward each other at the same time from two towns that are 500 miles apart. After three hours the trains are still 80 miles apart. If the rate of the passenger train is 20 miles per hour faster than the rate of the freight train, find the rate of each train.
:
Let s = speed of the freight
then
Let (s+20) = speed of the passenger
:
Write a dist equation: Dist = time * speed
:
Pass dist + Freight dist = total dist - 80 mi
3(s+20) + 3s = (500 - 80)
:
3s + 60 + 3s = 420
:
6s = 420 - 60
:
6s = 360
s =
s = 60 mph, speed of the freight, then 80 mph = speed of the pass train;
:
:
Check:
3(80) + 3(60) = 500 - 80
240 + 180 = 420
:
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