SOLUTION: If a square has a diagonal of {{{ 8 sqrt (2) }}}. What is the length of a side?

Question 134800: If a square has a diagonal of . What is the length of a side?
Found 3 solutions by vleith, stanbon, solver91311:
Answer by vleith(2983)   (Show Source): You can put this solution on YOUR website!
Use Pythagorean theorem
a^2 + b^2 = c^2
C is the diagonal. Since we have a square, a = b
a^2 + a^2 = (8*sqrt(2))^2
2a^2 = 128
a^2 = 64
a = 8

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
If a square has a diagonal of . What is the length of a side?
--------------------
Let the side be "x"
EQUATION:
x^2 + x^2 = (8sqrt(2))^2
2x^2 = 64*2
x^2 = 64
x = 8 (each sie is length = 8
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Cheers,
Stan H.
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
The diagonal of a square forms an isoceles right triangle with two of the sides. Using Pythagoras, and remembering that the legs of the triangle are the same length, we have , and since , . That means:

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