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In ∆ PQR, │PQ│= 9cm, │QR│= 11cm, │RP│= 7cm and the bisector of ln ∠P meets line QR at T.
Calculate │QT│ and│TR│.
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In every triangle, every its angle bisector has this remarkable property:
the foot of the angle bisector divides the side of the triangle
in the ratio equal to the ratio of the adjacent sides.
Therefore, in triangle PQR, the bisector PT of angle P
divide the side QR of 11 cm long in the ratio
= , (1)
or
= . (2)
Together with QT + TR = QR = 11 cm, it gives
QT = = cm = 6 cm, (3)
TR = = cm = 4 cm. (4)
ANSWER. QT = = cm = 6 cm; TR = = cm = 4 cm.
Solved.
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Try to deduce formulas (3) and (4) from formula (2) on your own.